Exercises with Solutions in Radiation Physics by Andrew Laister

Author:Andrew Laister
Language: eng
Format: epub
Published: 2015-12-05T16:00:00+00:00

Q = -2mec2 + 2mec2=0 as the production of the electron-positron pair is compensated by the annihilation of the positron.

As hν = T1 + T2 + 2mec2 the energy imparted can be expressed as

The energy transferred is

With hν = T1 + T2 + 2me c2 and Q=0 the energy transferred tr can be expressed as

Figure 4.1: Energy transfer in a small cavity. A photon with the energy hν enters the cavity and undergoes pair production, resulting in an electron-positron pair. The positron is absorbed in the cavity and produces two annihilation photons, but the electron leaves the cavity with the energy T3.

The energy transferred is thus the kinetic energy transferred to the charged particles in the volume.

The net energy transferred will be

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